Ah, also I should note that using braces for exponents in l3fp is
wrong. It turns out to work incidentally, because these specific
braces are basically ignored, so you get (1+1/1010)^1010.
On 7/10/14, Bruno Le Floch <[log in to unmask]> wrote:
> Hello Andrew,
>
> Very clearly a bug. Comes from a bug in the log function (well, the
> more precise internal version that is used when computing powers) in
> the range [1.00099009, 1.0009901) it seems, and probably some other
> ranges. I'll investigate.
>
> Also, I'll likely answer at some point in the next couple of days to
> your juxtaposition email. Sorry for the delay.
>
> Regards,
> Bruno
>
> On 6/18/14, aparsloe <[log in to unmask]> wrote:
>> \fp_eval:n { exp(1)  (1+1/1009)^{1009} } > 0.001346
>> \fp_eval:n { exp(1)  (1+1/1010)^{1010} } > 0.001613
>> \fp_eval:n { exp(1)  (1+1/1011)^{1011} } > 0.001343
>
