Hi all,

sorry for this rather trivial question, but at the moment it's driving
me crazy …
I just want to execute some code depending on the jobname. I found a
solition by Donald Arsenau¹ that looks rather lengthy. So, I thought
with LaTeX3, everything is easier. Now I tried this:

\documentclass{minimal}
\usepackage{expl3}
\begin{document}
\ExplSyntaxOn
\tl_set:Nn\myjob{a}
\tl_set:Nx\myjobii{\tl_to_str:N\myjob}
\tl_if_eq:NNTF\myjobii\jobname{true}{false}
\ExplSyntaxOff
\end{document}

because, based on Donald's post, I assumed that I need to have an “a”
with catcode “other” for a successfull test.

Now, calling
lualatex --jobname=a test.tex
always prints “false”. So – what is my mistake here and what would be
the easiest way for such a test using expl3?

cheers
Arno